Initial velocity of the stone, u = 20 m/s
Final velocity of the stone, v = 0 m/s
Distance covered by the stone, s = 50 m
According to the third equation of motion:
v 2 = u 2 + 2as
Where,
Acceleration, a
(0)2 = (20)2 + 2 × a × 50
a = – 4 m/s2
The negative sign indicates that acceleration is acting against the motion of the stone.
Mass of the stone, m = 1 kg
From Newton's second law of motion:
Force, F = Mass x Acceleration
F= ma
F= 1 × (– 4) = – 4 N
Hence, the force of friction between the stone and the ice is – 4 N.
