The function f(x) is an even function and satisfies x^2f(x)-2f(1/x)=g(x) where g(x) is an odd function.The value of f(5) is

+2 votes
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asked Oct 29, 2017 in Mathematics by AMIT KUMAR (150 points) 6
edited Oct 29, 2017 by Abhishek Kumar

The function f(x) is an even function and satisfies x2f(x)-2f(1/x)=g(x) where g(x) is an odd function.The value of f(5) is

(a)-2         (b)4                       (c)0                     (d)depends on g(x)                (e)NOT 

1 Answer

+1 vote
answered Oct 29, 2017 by Abhishek Kumar (14,593 points) 5 9 35
 
Best answer

The answer will be (c) i.e F(5)=0

...g(x) and x2 are odd and even function respectively.

So, f(x) is an odd function . But f(x) is given even.

f(x)=0∀x , 

Hence f(5)=0

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