Question

Find the no of charge and no of electrons present in 400gm of Ca++

Answer 1

First Mole of Ca is 400/40=10

Charge on one Mole of electrons=Avogadro's No×Charge on electron=96500c=1 faraday

Now charge on one Mole of Ca2+ ions=2×9650coulomb=2faraday

So charge on 10 Mole of ca2+ ions=10×2=20faraday

Now no of molecule of Ca2+ in 10 Mole is 10Avogadro no.

And In one atom of Ca 2+ there is 18

So in 10×Avogadro no of molecule have 10×10×Avogadro no.