ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD (see Fig.).

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asked Nov 8, 2017 in Mathematics by jisu zahaan (28,760 points) 28 436 1090

ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD (see Fig.). Show that 

(i) ∆ APB ≅ ∆CQD 

(ii) AP = CQ

1 Answer

+1 vote
answered Nov 8, 2017 by sforrest072 (157,439 points) 63 448 1284
selected Nov 8, 2017 by jisu zahaan
 
Best answer

Given : ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on BD. 

To Prove : 

(i) ∆APB ≅ ∆CQD 

(ii) AP = CQ 

Proof : (i) In ∆APB and ∆CQD, we have 

∠ABP = ∠CDQ [Alternate angles] 

AB = CD [Opposite sides of a parallelogram] 

∠APB = ∠CQD [Each = 90°] 

∴ ∆APB ≅ ∆CQD [ASA congruence] 

(ii) So, AP = CQ [CPCT] Proved.

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