Question

Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? 

Answer 1

Let Reshma, Salma and Mandip be represented by R, S and M respectively. 

Draw OL ⊥ RS, 

OL² = OR² – RL² 

OL² = 5² – 3² [RL = 3 m, because OL ⊥ RS] 

= 25 – 9 = 16 

OL = 16 = 4

Now, area of triangle ORS = 1/ 2 × KR × 05 

= 1/ 2 × KR × 05 

Also, area of ∆ORS = 1/ 2 × RS × OL = 1/ 2 × 6 × 4 = 12 m² 

⇒ 1/ 2 × KR × 5 = 12 

⇒ KR = 12x 2/ 5 =24/ 5 = 4.8 m 

⇒ RM = 2KR 

⇒ RM = 2 × 4.8 = 9.6 m 

Hence, distance between Reshma and Mandip is 9.6 m Ans.