Here, h = 1 m, volume = 15.4 litres
= 15.4/ 1000 m3 = 0.0154 m3
Also, volume of the cylinderical vessel = π r2h
⇒ 0.0154 = 22/ 7 × r2 × 1
⇒ r2 = 0.0154 × 7/ 22 = 0.0049
⇒ r = 0.07 m
∴ Total surface area of the cylinder = 2πr (h + r)
= 2 × 22/ 7 × 0.07 (1 + 0.07) m2
= 44 × 0.01 × 1.07 m2 = 0.4708 m2
Hence, 0.4708 m2 of metal sheet would be needed Ans.
