Ask a Question

Find maximum and minimum value of sin2x+5 from second derivative test.

+2 votes
9 views
asked Nov 15, 2017 by Kumod kumar (55 points) ● 3
commented Nov 15, 2017 by Kumod kumar (55 points) ● 3
Sir, I'm  not getting your answer of my own question.

1 Answer

+2 votes
answered Nov 16, 2017 by Ankit Agarwal (28,847 points) ● 7 ● 34 ● 107

f(x)=sin 2x+5 

We know that, 

-1≤sinӨ≤1 

-1≤sin2x≤1 

Adding 5 on both sides, 

 -1+5≤sin2x+5≤1+5 

4≤sin2x+5≤6 

Hence  

Max value of f(x)=sin2x+5 will be 6 

Min value of f(x) =sin2x+5 will be 4

Related questions

+2 votes
1 answer
Find maximum and minimum value of sin2x+5 from second derivative test
asked Nov 15, 2017 by Kumod kumar (55 points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Related questions

© 2017 Sarthaks eConnect
Managed by Sarthaks Digitizing India
...