With a neat diagram explain the 7-celled, 8-nucleate nature of the female gametophyte.

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asked Dec 1, 2017 in Biology by mdsamim (213,225 points) 5 10 15

With a neat diagram explain the 7-celled, 8-nucleate nature of the female gametophyte.

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answered Dec 1, 2017 by sforrest072 (157,439 points) 61 410 947
selected Feb 23, 2018 by sarthaks
 
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The female gametophyte (embryo sac) develops from a single functional megaspore. This megaspore undergoes three successive mitotic divisions to form eight nucleate embryo sacs.
The first mitotic division in the megaspore forms two nuclei. One nucleus moves towards the micropylar end while the other nucleus moves towards the chalazal end. Then, these nuclei divide at their respective ends and re-divide to form eight nucleate stages. As a result, there are four nuclei each at both the ends i.e., at the micropylar and the chalazal end in the embryo sac. At the micropylar end, out of the
fournuclei only three differentiate into two synergids and one egg cell. Together they are known as the egg apparatus. Similarly, at the chalazal end, three out of four nuclei differentiates as antipodal cells. The remaining two cells (of the micropylar and the chalazal end) move towards the centre and are known as the polar nuclei, which are situated in a large central cell. Hence, at maturity, the female gametophyte appears as a 7-celled structure, though it has 8 nucleate.

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