Solution:
Let the two consecutive odd positive integers be x and x + 2.
x < 10, x + 2 < 10, x + (x + 2) > 11
x + 2 < 10
x < 8
x + (x + 2) > 11
2x + 2 > 11
2x > 9
x > 9/2
i.e 8 > x > 9/2
Thus, the required pairs of consecutive odd positive integers are (5, 7) and (7, 5).