Question

Silver crystallises in fcc lattice. If edge length of the cell is 4.07 × 10⁻⁸ cm and density is 10.5 g cm⁻³, calculate the atomic mass of silver.

Answer 1

It is given that the edge length, a = 4.077 × 10⁻⁸ cm Density,

 d = 10.5 g cm⁻³ 

As the lattice is fcc type, the number of atoms per unit cell, z = 4

 We also know that

 N_A = 6.022 × 10²³ mol⁻¹ Using the relation: