An element with molar mass 2.7 × 10^-2 kg/mol forms a cubic unit cell with edge length 405 pm.

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asked Dec 12, 2017 in Chemistry by sforrest072 (157,439 points) 63 447 1241

An element with molar mass 2.7 × 10-2 kg mol-1 forms a cubic unit cell with edge length 405 pm. If its density is 2.7 × 103 kg m−3, what is the nature of the cubic unit cell?

1 Answer

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answered Dec 12, 2017 by mdsamim (213,225 points) 5 10 21
selected Mar 4, 2018 by sarthaks
 
Best answer

It is given that density of the element, d = 2.7 × 103 kg m−3 

Molar mass, M = 2.7 × 10−2 kg mol−1
Edge length, a = 405 pm = 405 × 10−12 m
= 4.05 × 10−10 m
It is known 
that, Avogadro’s number, NA = 6.022 × 1023 mol−1 

Applying the relation,

This implies that four atoms of the element are present per unit cell. Hence, the unit cell is face-centred cubic (fcc) or cubic close-packed (ccp).

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