Question

The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10−3 S cm−¹ . 

Answer 1

Given,

 Conductivity, κ = 0.146 × 10−3 S cm−1 Resistance, R = 1500 Ω

 Cell constant = κ × R

 = 0.146 × 10−³ × 1500

 = 0.219 cm−¹