Solution: We have
Mass percent of HNO3=69%
Hence mass of HNO3 in the solution is 69g
Mass of water=100-69=31g
Number of moles of HNO3 =69/63=1.09moles
Density=mass/volume
Volume=mass/density
=100/1.41=70.9ml
Concentration (Molarity) = number of moles of solute/volume of the solution
= (1.09/70.9)×100
= 1.5M