Question

Following reaction takes place in one step :
2NO + O_{2 =>} 2NO₂

How will the rate of the reaction of the above reaction change if the volume
of reaction vessel is diminished to 1/3 of its original volume ? Will there be
any change in the order of reaction with reduced volume ?

Answer 1

[Since it is one step.]
If the volume of reaction vessel is diminished to 1/3, conc. of both NO and O₂
will become 3 times, the rate of reaction increased 27 times in the order of reaction
with the reduced volume.