Question

The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate E_a.

Answer 1

It is given that T₁ = 298 K
T₂ = (298 + 10) K
= 308 K

We also know that the rate of the reaction doubles when temperature is increased by 10°.
Therefore, let us take the value of k₁ = k and that of k₂ = 2k
Also, R = 8.314 J K⁻¹ mol⁻¹
Now, substituting these values in the equation:

Note: There is a slight variation in this answer and the one given in the NCERT textbook.