Knowing the electron gain enthalpy values for O → O− and O → O2− as −141 and 702 kJ mol−1 respectively,

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asked Dec 22, 2017 in Chemistry by sforrest072 (157,439 points) 63 448 1290

Knowing the electron gain enthalpy values for O → O− and O → O2− as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O−?
(Hint: Consider lattice energy factor in the formation of compounds).

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answered Dec 22, 2017 by mdsamim (213,225 points) 5 10 23
selected Dec 22, 2017 by sforrest072
 
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Stability of an ionic compound depends on its lattice energy. More the lattice energy of a
compound, more stable it will be. Lattice energy is directly proportional to the charge carried by an ion. When a metal combines with oxygen, the lattice energy of the oxide involving O2− ion is much more than
 the oxide involving O− ion. Hence, the oxide having O2− ions are more stable than oxides
having O−. Hence, we can say that formation of O2− is energetically more favourable than formation of O−.

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