Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years.

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asked Dec 23, 2017 in Mathematics by Golu (37,045 points) 19 172 617

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

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answered Dec 23, 2017 by Golu (37,045 points) 19 172 617
 
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Let Baichung's father's present age be x years
Given Baichung's father is 29 years older than Baichung
Hence Baichung's age is (x − 29) years
Baichung's grandfather is 26 years older than Baichung's father.
Hence Baichung's grandfather's age = (x + 26) years
Given sum of three ages = 135 years
∴ x + (x − 29) +(x + 26) = 135
3x − 3 = 135
3x = 135 + 3  = 138
∴ x = 46
Baichung's father's age = 46 years
Baichung's grandfather's age = (x + 26) = (46 + 26) = 72 years
Baichung's age = (x − 29) = (46 − 29) = 17 years

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