In the series Sc (Z = 21) to Zn (Z = 30), the enthalpy of atomization of zinc is the lowest, i.e., 126 kJ mol−1. Why?

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asked Dec 25, 2017 in Chemistry by sforrest072 (157,439 points) 61 410 949

In the series Sc (Z = 21) to Zn (Z = 30), the enthalpy of atomization of zinc is the lowest,
i.e., 126 kJ mol−1. Why?

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answered Dec 25, 2017 by mdsamim (213,225 points) 5 10 15
selected Dec 25, 2017 by sforrest072
 
Best answer

The extent of metallic bonding an element undergoes decides the enthalpy of atomization. nThe more extensive the metallic bonding of an element, the more will be its enthalpy of atomization. In all transition metals (except Zn, electronic configuration: 3d10 4s2), there are some unpaired electrons that account for their stronger metallic bonding. Due to the
absence of these unpaired electrons, the inter-atomic electronic bonding is the weakest in Zn and as a result, it has the least enthalpy of atomization.

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