NCERT Class-8 Maths Factorisation Chapter-14.2

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asked Dec 27, 2017 in Mathematics by Golu (37,045 points) 19 145 415

Factorise the following expressions.

(i) a² + 8a + 16

(ii) p² – 10 p + 25

(iii) 25m² + 30m + 9

(iv) 49y² + 84yz + 36z²

(v) 4x² – 8x + 4

(vi) 121b² – 88bc + 16c²

(vii) (l + m)² – 4lm

(viii) a4 + 2a²b² + b4

1 Answer

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answered Dec 27, 2017 by Ankit Agarwal (28,847 points) 7 32 68
selected Dec 27, 2017 by Golu
 
Best answer

(i) a² + 8a + 16

Answer: This equation can be facorised by using the identity; (a + b)2 = a2 + 2ab + b2
Factors = (a + 4)2 = (a + 4)(a + 4)

(ii) p² – 10 p + 25

Answer: This equation can be factorised by using the identity; (a – b)2 = a2 – 2ab + b2
Factors = (p – 5)2

(iii) 25m² + 30m + 9

Answer: = (5m – 3)2

(iv) 49y² + 84yz + 36z²

Answer: (7y + 6z)2

(v) 4x² – 8x + 4

Answer: (2x – 2)2

(vi) 121b² – 88bc + 16c²

Answer: (11b – 4c)2

(vii) (l + m)² – 4lm

Answer: l2 + m2 + 2lm - 4lm
l2 + m2 - 2lm = (l + m)2

(viii) a4 + 2a²b² + b4

Answer: This can be solved using (a+b)² = a²+ 2ab + b²
Hence, a4 + 2a²b² + b4
=(a²+b²)²

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