NCERT Class-8 Maths Factorisation Chapter-14.3 Divide as directed:

Question

Divide as directed:

(a) 5(2x + 1)(3x + 5) ÷ (2x + 1)

(b) 26xy(x + 5) (y – 4) ÷ 13x (y -4)

(c) 52pqr(p + q) (q + r)( r + p) ÷ 104 pq(q + r)( r + p)

(d) 20 ( y + 4) (y² + 5y + 3) ÷ 5 (y + 4)

(e) x ( x + 1) ( x + 2) (x + 3) ÷ x( x + 1)

Answer 1

(a) 5(2x + 1)(3x + 5) ÷ (2x + 1)

Answer: 5(2x + 1)(3x + 5) ÷ (2x + 1)
= 5(3x + 5) = 15x + 25

(b) 26xy(x + 5) (y – 4) ÷ 13x (y -4)

Answer: 26xy(x + 5) (y – 4) ÷ 13x (y -4)
= 2y(x + 5)(y – 4) ÷(y – 4)
= 2Y (x + 5) = 2xy + 10y

(c) 52pqr(p + q) (q + r)( r + p) ÷ 104 pq(q + r)( r + p)

Answer: 52pqr(p + q) (q + r)( r + p) ÷ 104 pq(q + r)( r + p)
= r (p + q) (q + r) ( r + p) ÷ 2 (q + r) (r + p) 
= r (p + q) ÷ 2

(d) 20 ( y + 4) (y² + 5y + 3) ÷ 5 (y + 4)

Answer: 20 ( y + 4) (y2 + 5y + 3) ÷ 5 (y + 4)
= 4 (y + 4) (y2 + 5y + 3) ÷ (y + 4)
= 4(y2 + 5y + 3)

(e) x ( x + 1) ( x + 2) (x + 3) ÷ x( x + 1)

Answer: x ( x + 1) ( x + 2) (x + 3) ÷ x( x + 1)
= (x + 2)(x + 3)