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Arrange the following polymers in increasing order of their intermolecular forces. (i) Nylon 6, 6, Buna-S, Polythene.

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asked Dec 28, 2017 in Chemistry by sforrest072 (157,439 points) ● 61 ● 410 ● 949

Arrange the following polymers in increasing order of their intermolecular forces.
(i) Nylon 6, 6, Buna-S, Polythene.
(ii) Nylon 6, Neoprene, Polyvinyl chloride.

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answered Dec 28, 2017 by mdsamim (213,225 points) ● 5 ● 10 ● 15
selected Dec 28, 2017 by sforrest072
 
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Different types of polymers have different intermolecular forces of attraction. Elastomers or rubbers have the weakest while fibres have the strongest intermolecular forces of attraction. Plastics have intermediate intermolecular forces of attraction. Hence, the increasing order of the intermolecular forces of the given polymers is as follows: (i) Buna − S < polythene < Nylon 6, 6 (ii) Neoprene < polyvinyl chloride < Nylon 6

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