Question

Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

Answer 1

Given: BC = 48 m, CD = 17 m, AD = 40 m and perimeter = 120 m 

Perimeter of trapezium ABCD = AB + BC + CD + DA 

=> 120 = AB + 48 + 17 + 40

=> 120 = AB = 105

=> AB = 120 – 105 = 15 m

Hence, area of the field ABCD is 660 m².