A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80.0 μC/m^2.

+1 vote
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asked Jan 3, 2018 in Physics by sforrest072 (157,439 points) 60 409 936
edited Mar 4, 2018 by Vikash Kumar

A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80.0 μC/m2.
(a) Find the charge on the sphere.
(b) What is the total electric flux leaving the surface of the sphere?

1 Answer

+1 vote
answered Jan 3, 2018 by mdsamim (213,225 points) 5 10 15
edited Mar 4, 2018 by Vikash Kumar
 
Best answer

(a) Diameter of the sphere, d = 2.4 m

Radius of the sphere, r = 1.2 m
Surface charge density, = 80.0 μC/m2 = 80 × 10−6 C/m2
Total charge on the surface of the sphere,
Q = Charge density × Surface area

Therefore, the charge on the sphere is 1.447 × 10−3 C.

(b) Total electric flux (ϕTotal ) leaving out the surface of a sphere containing net charge Q is given by the relation,

ϕTotal =Q/εo

Where,
εo= Permittivity of free space
= 8.854 × 10−12 N−1C2 m−2
Q = 1.447 × 10−3

ϕTotal=(1.447×10−3) /(8.854×10−12)
= 1.63 × 108 N C−1 m2

Therefore, the total electric flux leaving the surface of the sphere is 1.63 × 108 N C−1 m2.

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