Question

The following concentrations were obtained for the formation of NH₃ from N₂ and H₂ at equilibrium at 500K. [N₂] = 1.5 × 10^–2M. [H₂] = 3.0 ×10^–2 M and [NH₃] = 1.2 ×10^–2M. Calculate equilibrium constant.

Answer 1

Given that..

[N₂]=1.5 x 10^–2M

[H₂]=3.0 x10^–2 M

[NH₃]=1.2 x 10^–2 M

Substituting the above values in above equation and calculating.

we get..

K = 3.55 x 10²