In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm

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asked Jan 4, 2018 in Physics by sforrest072 (157,439 points) 61 410 937

In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63.0 cm, what is the emf of the second cell

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answered Jan 4, 2018 by mdsamim (213,225 points) 5 10 15
edited Mar 5, 2018 by Vikash Kumar
 
Best answer

Emf of the cell, E1 = 1.25 V
Balance point of the potentiometer, l1= 35 cm The cell is replaced by another cell of emf E2.
New balance point of the potentiometer, l2 = 63 cm

Therefore, emf of the second cell is 2.25V.

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