Figure 3.34 shows a potentiometer circuit for comparison of two resistances.

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asked Jan 4, 2018 in Physics by sforrest072 (157,439 points) 61 411 949

Figure 3.34 shows a potentiometer circuit for comparison of two resistances. The balance point with a standard resistor R = 10.0 Ω is found to be 58.3 cm, while that with the unknown resistance X is 68.5 cm. Determine the value of X. What might you do if you failed to find a balance point with the given cell of emf ε?

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answered Jan 4, 2018 by mdsamim (213,225 points) 5 10 15
edited Mar 5, 2018 by Vikash Kumar
 
Best answer

Resistance of the standard resistor, R = 10.0 Ω

 Balance point for this resistance, l1 = 58.3 cm

 Current in the potentiometer wire = 

i Hence, potential drop across R, E1 = iR 

Resistance of the unknown resistor = X

 Balance point for this resistor, l2 = 68.5 cm 

Hence, potential drop across X, E2 = iX The relation connecting emf and balance point is,

Therefore, the value of the unknown resistance, X, is 11.75 Ω. 

If we fail to find a balance point with the given cell of emf, ε, then the potential drop across R and X must be reduced by putting a resistance in series with it. Only if the potential drop across R or X is smaller than the potential drop across the potentiometer wire AB, a balance point is obtained.

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