Question

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

Answer 1

Length of the wire, l = 3 cm = 0.03 m
Current flowing in the wire, I = 10 A
Magnetic field, B = 0.27 T
Angle between the current and magnetic field, θ = 90°
Magnetic force exerted on the wire is given as:

F=BIlsinθ
= 0.27 × 10 × 0.03 sin90°
= 8.1 × 10^–2 N
Hence, the magnetic force on the wire is 8.1 × 10^–2 N. The direction of the force can be obtained from Fleming’s left hand rule.