For a circular coil of radius R and N turns carrying current I, the magnitude

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asked Jan 4, 2018 in Physics by sforrest072 (157,439 points) 61 410 939
edited Mar 5, 2018 by Vikash Kumar

For a circular coil of radius R and N turns carrying current I, the magnitude of the magnetic field at a point on its axis at a distance x from its centre is given by,

(a) Show that this reduces to the familiar result for field at the centre of the coil.

(b) Consider two parallel co-axial circular coils of equal radius R, and number of turns N, carrying equal currents in the same direction, and separated by a distance R. Show that the field on the axis around the mid- point between the coils is uniform over a distance that is small as compared to R, and is given by, =0.72−(μoBNI)/R, approximately.
[Such an arrangement to produce a nearly uniform magnetic field over a small region is known as Helmholtz coils.]

1 Answer

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answered Jan 4, 2018 by mdsamim (213,225 points) 5 10 15
selected Mar 5, 2018 by Vikash Kumar
 
Best answer

Radius of circular coil = R
Number of turns on the coil = N
Current in the coil = I
Magnetic field at a point on its axis at distance x is given by the relation,

Hence, it is proved that the field on the axis around the mid-point between the coils is uniform.

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