Question

Without using distance formula, show that points (– 2, – 1), (4, 0), (3, 3) and (–3, 2) are the vertices of a parallelogram.

Answer 1

Let the vertices be A(-2, -1), B(4, 0), C(3, 3), D(-3, 2)

Now m_AB = m_CD ⇒ AB || CD

and m_BC = m_AD ⇒ BC || AD

Hence ABCD is a parallelogram.