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If the solenoid in Exercise 5.5 is free to turn about the vertical direction

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asked Jan 5, 2018 in Physics by sforrest072 (157,439 points) ● 61 ● 410 ● 943

If the solenoid in Exercise 5.5 is free to turn about the vertical direction and a uniform horizontal magnetic field of 0.25 T is applied, what is the magnitude of torque on the solenoid when its axis makes an angle of 30° with the direction of applied field?

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answered Jan 5, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 15
edited Mar 4, 2018 by Vikash Kumar
 
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Magnetic field strength, B = 0.25 T
Magnetic moment, M = 0.6 T−1
The angle θ, between the axis of the solenoid and the direction of the applied field is 30°. Therefore, the torque acting on the solenoid is given as:

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