A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s^−1

0 votes
29 views
asked Jan 5, 2018 in Physics by sforrest072 (157,439 points) 60 409 937
edited Mar 5, 2018 by Vikash Kumar

A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s−1 about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis exists everywhere. Calculate the emf developed between the centre and the ring.

1 Answer

0 votes
answered Jan 5, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 5, 2018 by sforrest072
 
Best answer

Length of the rod, l = 1 m
Angular frequency,ω = 400 rad/s
Magnetic field strength, B = 0.5 T
One end of the rod has zero linear velocity, while the other end has a linear velocity of
lω.

Hence, the emf developed between the centre and the ring is 100 V.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...