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Find the oxidation number of S in H2S2O7

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+5 votes
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asked Feb 3, 2017 in Chemistry by Rohit Singh (61,782 points) ● 35 ● 133 ● 357

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+5 votes
answered Feb 3, 2017 by vikash (21,277 points) ● 4 ● 19 ● 70
selected Feb 3, 2017 by Rohit Singh
 
Best answer

The oxidation state of Sulphur in H2S2O7 is +6

H = +1 
O = - 2 
2 + 2x - 14 = 0 
2x = 12 
x = +6

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