A series LCR circuit with L = 0.12 H, C = 480 nF, R = 23 Ω is connected to a 230 V variable frequency supply.

0 votes
35 views
asked Jan 6, 2018 in Physics by sforrest072 (157,439 points) 60 409 936
edited Mar 5, 2018 by Vikash Kumar

A series LCR circuit with L = 0.12 H, C = 480 nF, R = 23 Ω is connected to a 230 V variable frequency supply. 

(a) What is the source frequency for which current amplitude is maximum? Obtain this maximum value. 

(b) What is the source frequency for which average power absorbed by the circuit is maximum? Obtain the value of this maximum power.

(c) For which frequencies of the source is the power transferred to the circuit half the power at resonant frequency? What is the current amplitude at these frequencies? 

(d) What is the Q-factor of the given circuit?

1 Answer

0 votes
answered Jan 6, 2018 by mdsamim (213,225 points) 5 10 15
edited Mar 5, 2018 by Vikash Kumar
 
Best answer

Inductance, L = 0.12 H 

Capacitance, C = 480 nF = 480 × 10−9 F

 Resistance, R = 23 Ω 

Supply voltage, V = 230 V 

Peak voltage is given as:

(a) Current flowing in the circuit is given by the relation,

Hence, resonant frequency​ (VR) is 663.48 Hz.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...