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In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 10^10 Hz and amplitude 48 V m^−1.

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asked Jan 6, 2018 in Physics by sforrest072 (157,439 points) ● 61 ● 410 ● 940
edited Mar 5, 2018 by Vikash Kumar

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 1010 Hz and amplitude 48 V m−1.
(a) What is the wavelength of the wave?
(b) What is the amplitude of the oscillating magnetic field?
(c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 × 108 m s−1.]

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answered Jan 6, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 15
edited Mar 5, 2018 by Vikash Kumar
 
Best answer

Frequency of the electromagnetic wave, ν = 2.0 × 1010 Hz
Electric field amplitude, E0 = 48 V m−1
Speed of light, c = 3 × 108 m/s
(a) Wavelength of a wave is given as:

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