A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm.

0 votes
52 views
asked Jan 6, 2018 in Physics by sforrest072 (157,439 points) 63 448 1264

A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm. What is the area of the surface of water through which light from the bulb can emerge out? Refractive index of water is 1.33. (Consider the bulb to be a point source.)

1 Answer

0 votes
answered Jan 6, 2018 by mdsamim (213,225 points) 5 10 21
edited Mar 5, 2018 by Vikash Kumar
 
Best answer

Actual depth of the bulb in water, d1 = 80 cm = 0.8 m 

Refractive index of water,

 The given situation is shown in the following figure:

Hence, the area of the surface of water through which the light from the bulb can emerge is approximately 2.61 m2.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...