(a) Figure 9.35 shows a cross-section of a ‘light pipe’ made of a glass fibre of refractive index 1.68.

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asked Jan 8, 2018 in Physics by sforrest072 (157,439 points) 60 409 937

(a)  Figure 9.35 shows a cross-section of a ‘light pipe’ made of a glass fibre of refractive index 1.68. The outer covering of the pipe is made of a material of refractive index 1.44. What is the range of the angles of the incident rays with the axis of the pipe for which total reflections inside the pipe take place, as shown in the figure.

 (b) What is the answer if there is no outer covering of the pipe?

1 Answer

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answered Jan 8, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 8, 2018 by sforrest072
 
Best answer

(a) Refractive index of the glass fibre, 

Refractive index of the outer covering of the pipe, =  

  Angle of incidence = i 

Angle of refraction = r 

Angle of incidence at the interface = i’

The refractive index (μ) of the inner core − outer core interface is given as:

For the critical angle, total internal reflection (TIR) takes place only when, i.e., i > 59°

Thus, all the rays incident at angles lying in the range 0 < i < 60° will suffer total internal reflection.

(b) If the outer covering of the pipe is not present, then:

Refractive index of the outer pipe, 

For the angle of incidence i = 90°, we can write Snell’s law at the air − pipe interface as:

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