For a normal eye, the far point is at infinity and the near point of distinct vision is about 25cm in front of the eye.

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asked Jan 8, 2018 in Physics by sforrest072 (157,439 points) 60 409 937

For a normal eye, the far point is at infinity and the near point of distinct vision is about 25cm in front of the eye. The cornea of the eye provides a converging power of about 40 dioptres, and the least converging power of the eye-lens behind the cornea is about 20 dioptres. From this rough data estimate the range of accommodation (i.e., the range of converging power of the eye-lens) of a normal eye.

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answered Jan 8, 2018 by mdsamim (213,225 points) 5 10 15
edited Mar 5, 2018 by Vikash Kumar
 
Best answer

Least distance of distinct vision, d = 25 cm

To focus an object at the near point, object distance (u) = −d = −25 cm Focal length of the eye-lens = Distance between the cornea and the retina = Image distance

Power of the eye-lens = 64 − 40 = 24 D 

Hence, the range of accommodation of the eye-lens is from 20 D to 24 D.

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