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The photoelectric cut-off voltage in a certain experiment is 1.5 V.

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asked Jan 8, 2018 in Physics by sforrest072 (157,439 points) ● 63 ● 451 ● 1313

The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?

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answered Jan 8, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 24
edited Mar 5, 2018 by Vikash Kumar
 
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Photoelectric cut-off voltage, V0 = 1.5 V
The maximum kinetic energy of the emitted photoelectrons is given as:

Therefore, the maximum kinetic energy of the photoelectrons emitted in the given  experiment is 2.4 × 10−19 J.

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