Question

Obtain an expression for the frequency of radiation emitted when a hydrogen atom deexcites from level n to level (n−1). For large n, show that this frequency equals the classical frequency of revolution of the electron in the orbit.

Answer 1

It is given that a hydrogen atom de-excites from an upper level (n) to a lower level (n−1). 

We have the relation for energy (E₁) of radiation at level n as:

Classical relation of frequency of revolution of an electron is given as:

Hence, the frequency of radiation emitted by the hydrogen atom is equal to its classical orbital frequency.