The given fusion reaction is:
It can be inferred from the given reaction that when two atoms of deuterium fuse, 3.27 MeV energy is released. Total energy per nucleus released in the fusion reaction:
Power of the electric lamp, P = 100 W = 100 J/s
Hence, the energy consumed by the lamp per second = 100 J
The total time for which the electric lamp will glow is calculated as:
