Solution :
i) 26 and 91
26=2×13×1(expressing as product of it’s prime factors)
91=7×13×1(expressing as product of it’s prime factors)
So, LCM(26,91)=2×7×13×1=182
HCF(26,91)=13×1=13
Verification:
LCM×HCF=13×182=2366
Product of 26 and 91 =2366
Therefore,LCM×HCF=Product of the two numbers .
i) 510 and 92
510=2×3×17×5×1(expressing as product of it’s prime factors)
92=2×2×23×1(expressing as product of it’s prime factors)
So,
LCM(510,92)=2×2×3×5×17×23=23,460
HCF(510,92)=2
Verification:
LCM×HCF=23,460×2=46,920
Product of 510 and 92 =46,920
Therefore,LCM×HCF=Product of the two numbers .
iii) 336 and 54
336=2×2×2×2×7×3×1(expressing as product of it’s prime factors)
54=2×3×3×3×1(expressing as product of it’s prime factors)
So,
LCM(336,54)=24×33×7=3024
HCF(336,54)=2×3=6
Verification:
LCM×HCF=3024×6=18,144
Product of 336 and 54=18,144
Therefore,LCM×HCF=Product of the two numbers .