Solution: Let α, β and ɣ be the roots of the cubic polynomial
Given (α + β + ɣ) = 2
(αβ+ βɣ + ɣα) = – 7 and (αβɣ) = –14
The cubic polynomial with roots α, β and ɣ is x3 – (α + β + ɣ)x2 + (αβ+ βɣ + ɣα)x – (αβɣ) = 0
⇒ x3 – (2)x2 + ( – 7 )x – ( – 14) = 0
⇒ x3 – 2x2 – 7x + 14 = 0