Find the zeroes of the polynomial mx^2 + (m + n) x + n.

+1 vote
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asked Apr 10, 2017 in Mathematics by Annu Priya (18,055 points) 24 45 84

1 Answer

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answered Apr 10, 2017 by sarthaks (25,122 points) 9 24 36
 
Best answer

Solution:

mx2+(m+n)x+n

=mx2+mx+nx+n

=mx(x+1)+n(x+1)

=(mx+n)(x+1)

So, x = -n/m or x = -1

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