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dy/dx : y= tan -1 ( 3x-x^3/ 1-3x^2), -1/√3 < x < 1/√3

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asked Jan 18, 2018 in Mathematics by sforrest072 (157,439 points) ● 61 ● 410 ● 949
edited Mar 7, 2018 by Vikash Kumar

Find dy/dx : 

y= tan -1 ( 3x-x3/ 1-3x2),  -1/√3 < x < 1/√3 

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answered Jan 18, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 15
selected Jan 18, 2018 by sforrest072
 
Best answer

The given relationship is 

  

Differentiating this relationship with respect to x, we obtain

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