A compound C (molecular formula, C2H4O2) reacts with Na-metal to form a compound R and evolves a gas which

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asked Jan 18, 2018 in Chemistry by sameer (82,980 points) 5 11 37
edited Jan 29, 2018 by Vikash Kumar

A compound C (molecular formula, C2H4O2) reacts with Na-metal to form a compound R and evolves a gas which burns with a pop sound. Compound C on treatment with an alcohol A in presence of an acid forms a sweet-smelling compound S (molecular formula C3H6O2). On addition of NaOH to C, it also gives R and water. S on treatment with NaOH solution gives back R and A.

Identify C,R,A and write down the reaction involved

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answered Jan 18, 2018 by faiz (82,347 points) 6 6 11
selected Jan 29, 2018 by Vikash Kumar
 
Best answer

C---Ethanoic acid
R --- Sodium salt of ethanoic acid (sodium acetate) and gas evolved is hydrogen
A --- Methanol
S --- Ester (Methyl acetate)

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