On dividing x^3 – 3x^2 + x + 2 by a polynomial g(x), the quotient and remainder were x – 2 and –2x + 4, respectively. Find g(x).

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asked Apr 13, 2017 in Mathematics by sforrest072 (157,439 points) 60 409 933

1 Answer

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answered Apr 13, 2017 by vikash (21,277 points) 4 19 70
 
Best answer

Here in the given question,

Dividend = x3 - 3x2 + x + 2

Quotient = x - 2

Remainder = -2x + 4

Divisor = g(x)

We know that,

Dividend = Quotient × Divisor + Remainder

⇒ x3 - 3x2 + x + 2 = (x - 2) × g(x) + (-2x + 4)⇒ x3 - 3x2 + x + 2 - (-2x + 4) = (x - 2) × g(x)
⇒ x3 - 3x2 + 3x - 2 = (x - 2) × g(x)
⇒ g(x) =  (x3 - 3x2 + 3x - 2)/(x - 2) 

 

∴ g(x) = (x2 - x + 1)

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