Question

The atomic numbers of nitrogen, oxygen and fluorine are 7 , 8 and 9 respectively. Write the electronic configuration of each element and answer the following questions:
(a) Which one of N, O and F is most electronegative and which one is least electronegative?
(b) What is the number of valence electrons of F?
(c) What is valency of each one of N, O and F?

Answer 1

Electronic configuration of
Nitrogen : 2,5
Oxygen: 2, 6
Fluorine: 2.7
(a) Fluorine (F) is most electronegative and nitrogen (N) is least electronegative.
(b) Fluorine (F) has 7 valence electrons.
(c) Valency of nitrogen is 3 and 5. valency of oxygen is 2, valency of fluorine is 1.