Question

If e^y (x+1) =1 , show that d²y/dx² = (dy/dx)²

Answer 1

The given relationship is e^y (x+1)=1

e^y (x+1) =1

=> e^y = 1/(x+1)

Taking logarithm on both the sides, we obtain

y= log 1/(x+1)

Differentiating this relationship with respect to x, we obtain

Hence, proved.