If x√(1+y)+y √(1+x) =0 -1 < x < 1, prove that dy/dx =1/(1+x)^2

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asked Jan 19, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 949

If x√(1+y)+y √(1+x) =0 -1 < x < 1, prove that dy/dx =1/(1+x)2

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answered Jan 19, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 19, 2018 by sforrest072
 
Best answer

It is given that,

Differentiating both sides with respect to x, we obtain

Hence, proved.

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