How many terms of the AP : 9, 17, 25, . . . must be taken to give a sum of 636?

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asked Apr 25, 2017 in Mathematics by sforrest072 (157,439 points) 60 409 933

1 Answer

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answered May 8, 2017 by sarthaks (25,122 points) 9 24 36
 
Best answer

The A.P. is given by  9, 17, 25, .........

First term, a = 9

Common difference, d = 17 - 9 = 25 - 17 = 8

Let n be the number of terms for which the sum is 636.

∴Sum of n terms, Sn = 636

As the number of terms can not be negative, therefore, n = 12.

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